25 500 ₴
IPhone 15 Pro з гарантіею
25500.0
Полтава
Знайдено 51 оголошення
{
"query": {
"bool": {
"must": [
{
"multi_match": {
"query": "iphone 15 pro",
"fields": [
"name^3",
"description",
"city^2"
],
"type": "best_fields",
"operator": "and",
"fuzziness": "AUTO",
"prefix_length": 2
}
}
],
"filter": [
{
"term": {
"city_id": 128
}
}
]
}
},
"sort": [
"_score",
{
"data_post": {
"order": "desc"
}
}
],
"from": 0,
"size": 50,
"_source": [
"id",
"m2",
"km",
"price2",
"attribute"
],
"track_total_hits": true,
"aggs": {
"cats": {
"terms": {
"field": "category_id",
"size": 2000
}
}
}
}SELECT c.* FROM `category` c ORDER BY c.id · 2.46 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["poltava","\/poltava","poltava\/","\/poltava\/"] · 1.63 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 0.69 msSHOW TABLES · 0.73 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [206837997,201624761,205853372,205431146,204313998,203087761,197462858,186255246,184986897,196224497,208731886,208731337,207067049,203436983,202835383,202700632,202570447,201380779,200896669,200457598,200265826,200117695,199480147,197895502,188003424,205019312,204418454,204356270,204245127,200823280,200265916,199074091,206838126,206036903,205720625,204589064,205720613,205720598,201711911,204314343,198769096,198975022,202701157,173791438,207188395,201451222,195388757,192973687,205501532,209787896] · 36.44 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [173791438,184986897,186255246,188003424,192973687,195388757,196224497,197462858,197895502,198769096,198975022,199074091,199480147,200117695,200265826,200265916,200457598,200823280,200896669,201380779,201451222,201624761,201711911,202570447,202700632,202701157,202835383,203087761,203436983,204245127,204313998,204314343,204356270,204418454,204589064,205019312,205431146,205501532,205720598,205720613,205720625,205853372,206036903,206837997,206838126,207067049,207188395,208731337,208731886,209787896] · 5.11 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 1.43 ms