11 500 $
Трикімнатна квартира в Підгородній
63 м² 506000.0
Підгородна
Знайдено 28 оголошень
{
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{
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21,
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{
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}SELECT c.* FROM `category` c ORDER BY c.id · 10.45 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["podgorodnaya","\/podgorodnaya","podgorodnaya\/","\/podgorodnaya\/"] · 1.41 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 0.42 msSHOW TABLES · 1.04 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [217974053,217488919,217411915,215669087,214353810,214080892,213842349,213136509,212976297,212976165,212803383,211331502,209550970,208329616,206786188,205673810,204040464,203974872,203784858,203531477,203203544,202434323,201940335,201723805,190351008,182364730,171126643,169335742] · 161.22 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [169335742,171126643,182364730,190351008,201723805,201940335,202434323,203203544,203531477,203784858,203974872,204040464,205673810,206786188,208329616,209550970,211331502,212803383,212976165,212976297,213136509,213842349,214080892,214353810,215669087,217411915,217488919,217974053] · 24.15 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 1.85 msSELECT v.attribute_id, v.value, COUNT(*) AS cnt FROM (SELECT p.id FROM `post` p WHERE p.category_id IN (?,?,?,?,?,?,?,?,?,?,?,?) AND (1) ORDER BY p.id DESC LIMIT 3000) s JOIN `attribute_value` v ON v.post_id = s.id WHERE v.value IS NOT NULL AND v.value <> '' AND CHAR_LENGTH(v.value) <= 60 GROUP BY v.attribute_id, v.value [21,28,27,26,25,24,23,101,100,22,96,95] · 99.64 msSELECT a.id, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute` a WHERE a.id IN (?,?,?,?,?,?,?,?) [651,1,652,653,660,662,659,661] · 2.33 ms