1 100 $
Оренда просторого будинку біля Львова, с. Страдч, поруч із сосновим лісом
323 м² 48400.0
Stradch
Знайдено 19 оголошень
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}SELECT c.* FROM `category` c ORDER BY c.id · 3.23 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["stradch","\/stradch","stradch\/","\/stradch\/"] · 1.93 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 1.55 msSHOW TABLES · 1.1 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [218120134,216704788,214066664,213977118,210492803,210385088,204386288,199425649,198858052,196183160,195676964,192438364,190350234,189922248,189922119,187418943,182866944,180932341,167416525] · 34.11 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [167416525,180932341,182866944,187418943,189922119,189922248,190350234,192438364,195676964,196183160,198858052,199425649,204386288,210385088,210492803,213977118,214066664,216704788,218120134] · 17.94 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 1.87 msSELECT v.attribute_id, v.value, COUNT(*) AS cnt FROM (SELECT p.id FROM `post` p WHERE p.category_id IN (?,?,?) AND (1) ORDER BY p.id DESC LIMIT 3000) s JOIN `attribute_value` v ON v.post_id = s.id WHERE v.value IS NOT NULL AND v.value <> '' AND CHAR_LENGTH(v.value) <= 60 GROUP BY v.attribute_id, v.value [23,101,100] · 442.58 msSELECT a.id, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute` a WHERE a.id IN (?,?,?,?,?,?,?,?) [1,651,653,655,660,661,662,673] · 0.75 ms