500 $
Ділянка , будинок у курортній зоні Карпат 80 сот.Обмін
22000.0
Бориня
Знайдено 8 оголошень
{
"query": {
"bool": {
"filter": [
{
"terms": {
"category_id": [
21,
28,
27,
26,
25,
24,
23,
101,
100,
22,
96,
95
]
}
},
{
"term": {
"city_id": 10375
}
}
]
}
},
"sort": [
{
"data_post": {
"order": "desc"
}
},
{
"id": "desc"
}
],
"from": 0,
"size": 50,
"_source": [
"id",
"m2",
"km",
"price2",
"attribute"
],
"track_total_hits": true
}SELECT c.* FROM `category` c ORDER BY c.id · 42.22 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["borynya","\/borynya","borynya\/","\/borynya\/"] · 1.84 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 0.8 msSHOW TABLES · 2.4 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?) AND (1=1) [217521751,215589183,208996687,208181245,194458112,188895372,183925145,173521081] · 12.7 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [173521081,183925145,188895372,194458112,208181245,208996687,215589183,217521751] · 3.8 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 1.2 msSELECT v.attribute_id, v.value, COUNT(*) AS cnt FROM (SELECT p.id FROM `post` p WHERE p.category_id IN (?,?,?,?,?,?,?,?,?,?,?,?) AND (1) ORDER BY p.id DESC LIMIT 3000) s JOIN `attribute_value` v ON v.post_id = s.id WHERE v.value IS NOT NULL AND v.value <> '' AND CHAR_LENGTH(v.value) <= 60 GROUP BY v.attribute_id, v.value [21,28,27,26,25,24,23,101,100,22,96,95] · 481.46 msSELECT a.id, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute` a WHERE a.id IN (?,?,?,?,?,?,?,?) [1,651,652,660,662,661,659,653] · 1.95 ms