25 ₴
Оренда приміщень під склад, виробництво, ремонт техніки
4000 м² 25.0
Хащувате
Знайдено 24 оголошення
{
"query": {
"bool": {
"filter": [
{
"term": {
"city_id": 7994
}
}
]
}
},
"sort": [
{
"data_post": {
"order": "desc"
}
},
{
"id": "desc"
}
],
"from": 0,
"size": 50,
"_source": [
"id",
"m2",
"km",
"price2",
"attribute"
],
"track_total_hits": true
}SELECT c.* FROM `category` c ORDER BY c.id · 1.21 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["hashchevatoe","\/hashchevatoe","hashchevatoe\/","\/hashchevatoe\/"] · 1.76 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 0.44 msSHOW TABLES · 1.23 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [218981870,218187643,217425961,216973915,216924595,215484330,214968579,214717851,214712853,213607959,213078558,210692428,210676098,201520615,201455566,200178160,198253205,197837132,197620034,197250939,196786027,188284173,179343886,168454996] · 10.61 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [168454996,179343886,188284173,196786027,197250939,197620034,197837132,198253205,200178160,201455566,201520615,210676098,210692428,213078558,213607959,214712853,214717851,214968579,215484330,216924595,216973915,217425961,218187643,218981870] · 4.34 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 1.01 ms