8 599 ₴
Iphone 15 plus Icloud Bypass
8599.0
Харків
Знайдено 54 оголошення
{
"query": {
"bool": {
"must": [
{
"multi_match": {
"query": "iphone 15 plus",
"fields": [
"name^3",
"description",
"city^2"
],
"type": "best_fields",
"operator": "and",
"fuzziness": "AUTO",
"prefix_length": 2
}
}
],
"filter": [
{
"term": {
"city_id": 135
}
}
]
}
},
"sort": [
"_score",
{
"data_post": {
"order": "desc"
}
}
],
"from": 0,
"size": 50,
"_source": [
"id",
"m2",
"km",
"price2",
"attribute"
],
"track_total_hits": true,
"aggs": {
"cats": {
"terms": {
"field": "category_id",
"size": 2000
}
}
}
}SELECT c.* FROM `category` c ORDER BY c.id · 3.31 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["harkov","\/harkov","harkov\/","\/harkov\/"] · 0.51 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 0.27 msSHOW TABLES · 0.94 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [195135926,178407021,197068426,211815114,209033443,208296718,203381894,183937367,183159153,208945861,197705867,197172469,189893559,181230520,171714694,171714667,202960765,195818345,195817685,209423932,203948634,202960780,167554267,167050903,193087220,191456809,177514495,192938791,193803758,199381936,192418780,204589715,182683845,205368458,205853423,211025618,188300919,184082292,210532619,182683758,205240226,198348368,198504806,209522002,201380577,166970467,212443302,212715066,206838094,216118060] · 53.44 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [166970467,167050903,167554267,171714667,171714694,177514495,178407021,181230520,182683758,182683845,183159153,183937367,184082292,188300919,189893559,191456809,192418780,192938791,193087220,193803758,195135926,195817685,195818345,197068426,197172469,197705867,198348368,198504806,199381936,201380577,202960765,202960780,203381894,203948634,204589715,205240226,205368458,205853423,206838094,208296718,208945861,209033443,209423932,209522002,210532619,211025618,211815114,212443302,212715066,216118060] · 5.16 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 0.91 ms