19 900 ₴
Dell G3 ігровий ноутбук 120герц 1650ti
19900.0
Веселе
Знайдено 18 оголошень
{
"query": {
"bool": {
"filter": [
{
"terms": {
"category_id": [
53,
98,
60,
59,
58,
57,
56,
55,
54
]
}
},
{
"term": {
"city_id": 3205
}
}
]
}
},
"sort": [
{
"data_post": {
"order": "desc"
}
},
{
"id": "desc"
}
],
"from": 0,
"size": 50,
"_source": [
"id",
"m2",
"km",
"price2",
"attribute"
],
"track_total_hits": true
}SELECT c.* FROM `category` c ORDER BY c.id · 2.41 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["veseloe","\/veseloe","veseloe\/","\/veseloe\/"] · 1.6 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 0.58 msSHOW TABLES · 1.15 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [214130024,213766566,213446583,210749830,210353114,207874822,207528847,203324978,203271077,202769200,201382011,197116933,190876950,189795582,189122103,185966184,175638698,170721907] · 15.56 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [170721907,175638698,185966184,189122103,189795582,190876950,197116933,201382011,202769200,203271077,203324978,207528847,207874822,210353114,210749830,213446583,213766566,214130024] · 2.15 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 1.78 msSELECT v.attribute_id, v.value, COUNT(*) AS cnt FROM (SELECT p.id FROM `post` p WHERE p.category_id IN (?,?,?,?,?,?,?,?,?) AND (1) ORDER BY p.id DESC LIMIT 3000) s JOIN `attribute_value` v ON v.post_id = s.id WHERE v.value IS NOT NULL AND v.value <> '' AND CHAR_LENGTH(v.value) <= 60 GROUP BY v.attribute_id, v.value [53,98,60,59,58,57,56,55,54] · 73.29 ms