1 100 ₴
Симметрирующее устройство Р-104М
1100.0
Диканька
Знайдено 30 оголошень
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}SELECT c.* FROM `category` c ORDER BY c.id · 3.33 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["dikanka","\/dikanka","dikanka\/","\/dikanka\/"] · 2.81 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 6.54 msSHOW TABLES · 2.07 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [218664392,214334850,214131358,214065338,214060634,213875978,213770949,213242127,212936187,212444877,211303770,210896358,209994839,208512664,208199806,207422041,204950357,204667154,204505271,204505130,204359090,204318387,204022488,203574962,203160580,200203708,196878070,193032821,187214193,166970680] · 19.95 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [166970680,187214193,193032821,196878070,200203708,203160580,203574962,204022488,204318387,204359090,204505130,204505271,204667154,204950357,207422041,208199806,208512664,209994839,210896358,211303770,212444877,212936187,213242127,213770949,213875978,214060634,214065338,214131358,214334850,218664392] · 1.59 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 0.63 msSELECT v.attribute_id, v.value, COUNT(*) AS cnt FROM (SELECT p.id FROM `post` p WHERE p.category_id IN (?,?,?,?,?,?,?,?,?) AND (1) ORDER BY p.id DESC LIMIT 3000) s JOIN `attribute_value` v ON v.post_id = s.id WHERE v.value IS NOT NULL AND v.value <> '' AND CHAR_LENGTH(v.value) <= 60 GROUP BY v.attribute_id, v.value [53,98,60,59,58,57,56,55,54] · 27.15 ms