459 ₴
зимовий комбінезон для дівчинки
459.0
Щирець
Знайдено 20 оголошень
{
"query": {
"bool": {
"filter": [
{
"terms": {
"category_id": [
11,
20,
19,
18,
17,
16,
15,
14,
13,
12
]
}
},
{
"term": {
"city_id": 6574
}
}
]
}
},
"sort": [
{
"data_post": {
"order": "desc"
}
},
{
"id": "desc"
}
],
"from": 0,
"size": 50,
"_source": [
"id",
"m2",
"km",
"price2",
"attribute"
],
"track_total_hits": true
}SELECT c.* FROM `category` c ORDER BY c.id · 1.46 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.url IN (?, ?, ?, ?) LIMIT 1 ["shchirec","\/shchirec","shchirec\/","\/shchirec\/"] · 1.02 msSELECT c.id FROM `city` c WHERE c.parent_id = 0 LIMIT 2 · 1.2 msSHOW TABLES · 6.58 msSELECT p.id, p.category_id, p.city_id, p.region AS region_id, p.vendor AS vendor_id, p.name, p.description, p.name AS name_orig, p.price, p.currency, p.bargain, p.conditions, p.url, p.img, p.view AS views, p.data_post, p.data_edit, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS city_name, c.url AS city_slug FROM `post` p LEFT JOIN `city` c ON c.id = p.city_id WHERE p.id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND (1=1) [219460348,218349491,217115698,215017953,214160081,212204625,212104812,208342273,207922081,207572758,206800221,199425313,198472293,197926351,197725658,193366777,188339634,186158964,181367899,179488795] · 21.32 msSELECT v.post_id, v.attribute_id, v.value, COALESCE(NULLIF(a.name_ua, ''), NULLIF(a.name, '')) AS name FROM `attribute_value` v JOIN `attribute` a ON a.id = v.attribute_id WHERE v.post_id IN (?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?,?) AND v.value IS NOT NULL AND v.value <> '' ORDER BY a.id [179488795,181367899,186158964,188339634,193366777,197725658,197926351,198472293,199425313,206800221,207572758,207922081,208342273,212104812,212204625,214160081,215017953,217115698,218349491,219460348] · 2.7 msSELECT c.id, c.parent_id, c.url AS slug, COALESCE(NULLIF(c.name_ua, ''), NULLIF(c.name, '')) AS name, NULL AS name_loc FROM `city` c WHERE c.parent_id = ? LIMIT 3000 [5] · 5.22 msSELECT v.attribute_id, v.value, COUNT(*) AS cnt FROM (SELECT p.id FROM `post` p WHERE p.category_id IN (?,?,?,?,?,?,?,?,?,?) AND (1) ORDER BY p.id DESC LIMIT 3000) s JOIN `attribute_value` v ON v.post_id = s.id WHERE v.value IS NOT NULL AND v.value <> '' AND CHAR_LENGTH(v.value) <= 60 GROUP BY v.attribute_id, v.value [11,20,19,18,17,16,15,14,13,12] · 68.19 ms